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Is no solution the same thing as undefined?

womp womp

Does sqrt(x)=-I has a solution?

It has to be A because that is the only equation in which the value on the right can't be a principal square root.

There is a solution. If x is a member of the cyclic group defined by modulo 4, then the solution is x=2, and x-2 = x+2 = 0.

people hear me out: x+2=x-2 |-x, +2 x-x+2+2=0 4=0, if 2+2=5, 4 can be 0! Edit: I did not finish the video, before writing this for fun, now it's less fun, because it actually happened

For equation A this is what I got: since sqrt(x) = x ^(0.5), and since e^(i pi) = -1, then sqrt(x) = -1 can be written as: x ^ 0.5 = e ^ i pi 0.5 lnx = i pi ln x = 2i pi x = (e^2ipi) = (e^ipi)^2 = (-1)^2 = 1 which would mean that sqrt(1) = -1. While it may not be the principle root, that would be sqrt (1) = 1, it still seems like a valid solution to me.

"What’s wrong with this?" Ummm. Everything?

x is in a quantum wave state oscillating between -2 and +2, entangled with itself so that when it is in one state on one side of the equation, it is in the corresponding other state on the other side of the equation. So the solution is: 0 = 0 superposed with 4 = -4. 🤪

Exactly!

The ans is infinity

How did this turn into multiplication...

Sure, math would be a lot easier if you could just move things from one side to the other when it's convenient.

x can be 0,1,2 or 3 under Z mod 4

You know very well there's a completely valid and sound argument to say that x=1 is a valid solution.

I think the logic (which was wrong) was that if two terms are equal, they multiply to zero. Now, you could say that if x= -2 and +2, then the terms are equal and multiplied together they equal zero.

This video is an IQ test, if you look it more than 5 seconds you are an idiot and if you really discuss it you are an idiot with to much time

Graphically, lines are parallel with equal slopes, lines never intersect, no sol.

The fact that it didn't even said 2 as sqrt(4)..

Surprisingly, TikTok didn't tell that 0 = -4 🤭

Where do a 45° line that intercepts the y-axis at 2, and another 45° line that intercept the y-axis at -2, intercept each other? In other words, where do 2 distinct parallel lines intercept each other?

I miss the old mic

Terrible wording of the question

In complex numbers, |x - 2| = |x + 2| is fairly obviously just any purely imaginary number i.e. Re(x) = 0. But that's the only way to get anything even approximating a solution.

why can we not write 1 as i^4? or -1 as i^2?

In an engineering exam you can still get some marks for this answer if you substitute 2 in the original equation, giving 2 + 2 = 2 - 2, i.e 4 = 0, and write "There is obviously a mistake somewhere". And if the examiner sees the mistake is a simple typo you might even get nearly full marks.

Funnily enough, it has a solution x=1 in {N mod 2}. Just kidding, there's no 2 in {N mod 2}: there's only 0 and 1.

The very FIRST step of the proposed «solution» is totally wrong. There are NO solution as this define two parallel lines.

Only infinity could satisfy this equation but infinity is not a number

4 equals zero. Or not.

my approach was almost the same : x+2-2 = x - 2-2 =>x = x - 4 =>x-x = x -x - 4 =>0 = -4(The input is a contradiction: it has no solutions)

what a question 😅.

I prefer to have my students think about the problem. I would ask can you think of a number that when you add 2 to it or subtract 2 from it you get the same result. The answer is obviously no and hence no solution.

Yea I’m no calculus major, but I know enough about (X)’s to put all X’s on one side and everything else that you can on the other. And that gets 0X=-4, which is about as wonky as the first question.

You are SOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOO right! TikTok should be banned!!

The answer is - 3/2

bro's math skills are tweakin

That proposed solution is got to be a ragebait ,

You didn't mention one basic thing that is taught along with equation solving: always perform a test of correctness (maybe solution verification? don't know the exact english term, but you are surely taught to do it). Just try putting the discovered "solutions" into the original equation and if you get nonsense, you know you made a mistake somewhere.

I was wondering if you would say something about going from (x+2)(x-2) = 0 to x^2-2^2 = 0 Like... Why do that? First form is already solved equation. You can see +-2 answers right away from multiples. Why butcher it by opening the parentheses?

No, not "no solutions". It has no *finite* solutions. X = infinity is a solution. And since you cannot multiply infinity by 0, nor can you subtract infinity by infinity, the solution holds.

the new generation is starting to showcase that humanity is going down, Idiocracy movie was a documentary, and soon IQ90 will be the smartest man on the planet (that is after 2070, because you need all of those born before Y2K to be no more)

Could it be e^(2*pi*i*n), only for n=odd integer ? That is, excluding 1 and others from the domain.

Good video. Thank you.

"X" is a number variable.... addition and subtraction are two very different concepts ... BOTH sides are equal ?? ... you can't build bridges with this this math - so what's the point ??

My guy didn't even use the zero product property after his egregious step of moving the x-2.

Before I watch your video I'm going to say NO SOLUTION. How can there be ?

2 solutions y=x, y=x+4. 2 parallel lines that intersects at +-infinity

Considering the whoppers made in the first few steps of this solution, I don't think this person is ready to consider extended real number systems or modular arithmetic to save their ass as suggested elsewhere in these responses. I do like your "complete the problem" attitude. Fractions should always be reduced (16/64 is one of my favorites - "but I reduced it by crossing out the 6's") and indefinite integrals should always end with a "+ C" (unless you have more information about the function). Mark 'em down. Just because you "got the right answer" doesn't mean you did it properly.

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